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1) We have copper wire whose diameter is 5 mm.
The length of the U-shaped rail will be 5+5+5=15 cm;
the effective length of the cross bar will be 5 cm.
This means that the total R will be 0.0173 ohms.
2) Suppose B=0.5 T (a neodymium magnet) and that
dt=0.25 second. With the d(AREA)=25 cm^2 the
emf will be 0.01 volts. The current will be 1.15 A.
3) The voltage across the bar will 25% of the total
or 2.5 mV; its polarity can be measured with the
oscilloscope.
Note that the voltage on the cross
bar would be negligible is q 100 ohm galvanometer
was inserted into the loop.