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It seems to imply
that the electric current in the rigid frame is
due to static charges residing at the ends of
the sliding rod. But we know that this is not
true; we know that electric field lines in the
closed loop have no beginning and no end.
Suppose I remove the rigid frame over which
the rod was sliding. The same rod is moved in
a vacuum, still perpendiculary to the magnetic
field B. Are there going to be static charges of
opposite sign at the ends of the rod or not?