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Re: Self-inductance, a conceptual question



Lest someone get tied up in knots, my statements about transformers should
have included the condition "for a given primary current." In sum, the
(open) secondary emf is proportional to the product Np*Ns, FOR A GIVEN
PRIMARY CURRENT.
. . .
Consider a transformer with an open-circuited secondary. The emf induced
in
the secondary is proportional to both Np (since Phi and dPhi/dt are
proportional to Np) and Ns (since the turns are in series and the emf
dPhi/dt is induced in each secondary turn). Thus the secondary emf is
proportional to the product Np*Ns. . . .

Bob Sciamanda (W3NLV)
Physics, Edinboro Univ of PA (em)
trebor@velocity.net
http://www.velocity.net/~trebor