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Re: electrical power



----- Original Message -----
From: "John S. Denker" <jsd@MONMOUTH.COM>

Justin Parke wrote:

Does anyone have any notes written
about the distinction between P=VI and P=I^2R?

In an ohmic situation, there is no distinction.

In a non-ohmic situation, P=VI is exact and
I2^R has no physical significance.

I understand that the latter refers to
"joule heating loss" but I don't feel clear as to why.

P=IV is the Joule heating.

Anything else is an approximation at best.

I guess I don't understand the last part here. A specific example: I want
to supply a small town with electrical power. I need to supply
approximately 10 MW. I could try and do that at 100,000 V and 100 A, or at
100 V and 100,000 A. In both cases P = IV = 10MW. However, for whatever
the resistance of the wires delivering the power, I^2R will be quite
different.

Rick

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Saint Mary's College
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rtarara@saintmarys.edu

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