Re: test problem

[Bob Sciamanda <trebor@VELOCITY.NET>]

Brian objected:
> No, the questions are unreasonable. If the extra downward displacement is
> greater than the equilibrium displacement, then the possibility of coil
> binding is not excluded on the upward rebound.

I don't understand this objection - I would think coil "binding" (?) is a
function of other things having to do with the coil design and structure. As
g is made to go to zero (go to different planets, or just turn down gravity)
"the extra downward displacement" becomes infinitely "greater than the
equilibrium displacement". You imply this worsens the situation!

>     For this same reason, the spring constant is not determined by only
the
> force required for a specified displacement.

I understand this statement even less.  Surely the static k is still
"determined by only the force required for a specified displacement".  Do
you refer to some "dynamic" k associated with the binding during
oscillation?



Bob Sciamanda (W3NLV)
Physics, Edinboro Univ of PA (em)
trebor@velocity.net
www.velocity.net/~trebor