Re: Problem

["RAUBER, JOEL" <JOEL_RAUBER@SDSTATE.EDU>]

Without really answering the second question, AFIK d|v|dt, as long as the
derivative is defined, it is the instantaneous component of acceleration
parallel to the instantaneous velocity; which is how it represents something
connected to acceleration.
Joel Rauber

> -----Original Message-----
> From: Michael Edmiston [mailto:edmiston@BLUFFTON.EDU]
> Sent: Tuesday, September 18, 2001 6:05 PM
> To: PHYS-L@lists.nau.edu
> Subject: Re: Problem
>
>
> Several people have been discussing d|v|/dt and whether it represents
> something connected to acceleration.  I am unaware of any such defined
> connection.  Has there ever been any official declaration
> that d|v|/dt means
> anything, i.e. have physicists ever officially attached any
> name to it?
>
> I like the question posed by someone earlier, which I'll
> expand here...  If
> v at the top is zero, and if a is zero or undefined, how does
> it get back
> down?  Or a similar question... which of the following would
> you like to
> choose: (1) gravity turned off for an instant (i.e. no force
> present at the
> top), (2) Newton's second law quit working for an instant
> (the force on the
> object due to being in a gravitational field momentarily did
> not cause any
> acceleration)?
>
>
> Michael D. Edmiston, Ph.D.              Phone/voice-mail:
>   419-358-3270
> Professor of Chemistry & Physics        FAX:
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