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Ahh, but we are told that tides are generated by the difference
between lunar and solar forces, so that the force equivalent to that of
the moon is generated by a satellite having 10^{-3} moon masses at a
distance (1/r_{moon})^{2} =10^{-3)/r^{2}, or
r = 10^{-3/2}r_{moon} = .03x60 earth radii or about 1.8 earth
radii.