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Re: Asteroid Problem



For quick calculations, it might be easier to look at slowing down or
speeding up the asteroid. While it depends on the angle of crossing
relative to the earth's path, I get something like a two minute change in
arrival time as enough to allow the earth to clear the asteroid path. This
is about a .0004% change (with 1 year lead time) which should require an
average speed change of less than 1 m/s (if the asteroid is moving at less
than a quarter-million meters/s). Plug in the mass and at least you can
easily get the force/energy needed.

Rick

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Richard W. Tarara
Professor of Physics
Saint Mary's College
Notre Dame, IN 46556
rtarara@saintmarys.edu

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----- Original Message -----
From: "Ludwik Kowalski" <kowalskiL@MAIL.MONTCLAIR.EDU>
To: <PHYS-L@lists.nau.edu>
Sent: Monday, August 27, 2001 10:16 AM
Subject: Re: Asteroid Problem


Thanks for constructive comments; I am not an astronomer.
Was the assumed speed, 10^5 m/s, realistic? In any case, it
would be useful to post an improved estimate of the amount
of energy needed to deviate an asteroid. Some of us may
like to present this problem to students but are not familiar
with realistic parameters. Can you help us, Michael?

Michael Bowen wrote (in part):

Also, 10^20 kg is a pretty hefty (although not inconceivable) asteroid;
if
made of water ice and trace metallic impurities, this implies a volume
of
10^20 liters or 10^17 m^3, and thus a radius (if spherical) of about 300
km, which is comparable to the sizes of the largest observed asteroids.
There are only a few of these known in the entire solar system. A more
common but still respectable chunk (say, the size of Eros) would cut the
radius by 10 and the mass, energy, momentum, and bomb count by an
additional factor of 10^3; I think that with these modifications we're
now
down to "only" 4 million bombs.

I think the needed angle of deflection is also less than 1/100 radian.
To
avoid a direct impact, one need only change the impact location by about
than 10^4 km (less, actually, but let's build in a safety factor; we
don't
want it exploding in the atmosphere during a near miss, a la Tunguska).
This is less than 10^-4 AU. From a distance of 100 AU, I think this
makes
the necessary deflection angle about a microradian. This is optimistic,
however, as astronomers are unlikely to spot an object of asteroid size
at
100 AU; it's simply too dim and far away.

Here's another question that I haven't calculated yet, but that might be
interesting: For a water-ice "asteroid" (probably "comet" would be a
better
description), how much heat would it take to simply boil the thing away
into space, and how would that compare with the energy required to
deflect
it? One wouldn't have to heat it to 373 K; once liquefied, the surface
should boil off readily into the surrounding vacuum, although one would
have to supply at least the heats of fusion and vaporization, the latter
of
which is still substantial. Could a fleet of small, warm, radioactive
robots "swim" through (or over) the ice to accomplish this, and could
such a fleet be safely recalled or otherwise disposed of (e.g., sent
into
the sun) after its work was finished?