Electrostatic shielding

[Bob Sciamanda <trebor@VELOCITY.NET>]

Typo correction:

One of the words "shell" should have been "charge" - see below:
Bob

----- Original Message -----
From: "Bob Sciamanda" <trebor@velocity.net>
To: "phys-l@lists.nau.edu: Forum for Physics Educators"
<PHYS-L@lists.nau.edu>
Sent: Wednesday, January 31, 2001 8:15 PM
Subject: Re: Electrostatic shielding

> You are too quick with the  "Nonsense!", Leigh:
>
> Consider a positive charge held "mechanically" at the center of a hollow,
> conducting (and isolated) spherical shell.  An equal negative charge will
> appear on the shell's inner surface and terminate the E lines from the
> central CHARGE  (not SHELL - the typo).   An equal positive charge will
appear on the shell's outer
> surface and produce an external field.
>
> E=0 only where there is conductor; there is a non-zero field everywhere
> else.
>
> Bob
>
> Bob Sciamanda (W3NLV)
> Physics, Edinboro Univ of PA (em)
> trebor@velocity.net
> www.velocity.net/~trebor
> ----- Original Message -----
> From: "Leigh Palmer" <palmer@SFU.CA>
> To: <PHYS-L@lists.nau.edu>
> Sent: Wednesday, January 31, 2001 5:29 PM
> Subject: Re: Electrostatic shielding
>
>
> > > On Wed, 31 Jan 2001, Lemmerhirt, Fred wrote:
> > >
> > > If you put a coulomb of charge inside a faraday cage, the cage itself
> > > seems to be charged with 1c, as if the flux lines go right through the
> > > walls of the cage.
> >
> > Nonsense! "Conductor" => E==0 !
> >
> > Leigh