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Hi all-there are
My complaint is that the whole discussion is muddy, which is why
Zannelli is getting conflicting answers. Different people evidently have
different ideas about what Zennelli is trying to ask.
His question appears to be based upon an out-of-context quote of
language from Adair. Adair, a fine physicist and talented writer, has
chosen for reasons of his own to invent the term "DeBroglie amplitude".
In order to understand the term, and the reason for inventing it, one must
read Adair, which I (and perhaps many others) have not. Zannelli
couples Adair's language with (apparently) a
recollection, of uncertain accuracy, of something Feynman wrote, which I
also have not seen.
It does seem clear that Zannelli's question has to do with the
rotation group, which was understood long before the advent of quantum
mechanics. It therefore seems that the question, whatever it is, can be
answered without reference to quantum measurements. I referred to
Weinberg, not for a statement of a "position", but for a place to find the
appropriate mathematical expression along with a brief explanation.
Regards,
Jack
On Sun, 24 Dec 2000, brian whatcott wrote:
Robert Zannelli appears to be comprising Feynman's explanation that
particletwo cycles of a spin two particle's state in 360 degrees of rotation.
This does not appear to contradict Weinberg's position that a one particle
integer spin state is invariant in 360 degrees of rotation (at least, to
an innocent bystander).
At 18:11 12/22/00 -0600, you wrote:
Hi all-given
This is unnecessarily complicated and confusing. The answer is
that a 1-particle bosonic (integer spin) state is invariant under a
360 degree rotation. A 1-particle fermionic state changes sign under such
a rotation.
End of story. For more detail see Weinberg, Vol. I, p. 89, where
you will see that the result is not quantum-mechanical but has to do
with representations of the Poincare' group.
Regards,
Jack
On Fri, 22 Dec 2000, Robert B Zannelli wrote:
OK Let me see if I get this. The number of a particles' eigenstates is
by the equation n=2s+1. Any particle will be not be in any defined state
until a measurement is made of that particles spin. An unmeasured
spin 2will be in a superposition of all it's possible eigenstates. For a
takeparticle there are 5 possible states which are-2,-1,0,1,2 . Now if we
Shouldand ourthe vector in the Hilbert space which defines the mix of these states
2 spin particle superposition states consist of only amplitudes in even
number states then a 180 degree rotation will be a complete cycle.
brian whatcott <inet@intellisys.net> Altus OKneed athere be any probability amplitude for any odd numbered state we would
360 degree rotation to complete a full cycle. In any case a 360 degree
rotation always returns the same amplitude.
brian whatcott <inet@intellisys.net> Altus OK
Eureka!
--
While [Jane] Austen's majestic use of language is surely diminished in its
translation to English, it is hoped that the following translation conveys
at least a sense of her exquisite command of her native tongue.
Greg Nagan from "Sense and Sensibility" in
<The 5-MINUTE ILIAD and Other Classics>