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...At 08:37 PM 1/2/00 -0600, brian whatcott wrote:
Temp (K) Res (ohms)
0.3 10^6
1 10^2
3 3
10 1
30 0.7
100 0.3 (from a graph of Rose-Innes's)
log(R) = 0.1136/sqrt(T) + 0.327
I was using log(R) = a - b*sqrt(T)
...I get quite different results, specifically
log(R) = 8.6/sqrt(T) - 2.7
with a *lot* of uncertainty in those coefficients and
pretty ugly looking residuals.
I get a far better fit to all but the 100 degree point with...
log(R) = 4.36/T - 0.5
John Mallinckrodt