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At 08:37 PM 1/2/00 -0600, brian whatcott wrote:
Temp (K) Res (ohms)
0.3 10^6
1 10^2
3 3
10 1
30 0.7
100 0.3 (from a graph of Rose-Innes's)
All the data except the 100K point lie in the range where I would expect a
simple fit to apply. ...
When I throw the fit I get
log(R) = 0.1136/sqrt(T) + 0.327
for this resistor.
This fits all the data modestly well. But there's so much curvature in the
graph of log(R) versus 1/sqrt(T) that I wouldn't be very happy using this
fit to interpolate or extrapolate near the low-temperature end (which is
where I would be most interested).