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Re: Symmetry in Lorentz transformation equations



You are right. I used a loose statement.

regards,

sarma.
At 02:12 PM 9/3/99 -0400, you wrote:
Since presence of mass is equivalent to accelerated frame,

Huh? I wouldn't have said that. At any given point, an accelerated frame
is equivalent to a gravitational field -- not to a mass _per se_.