Re: simple magnets question

[Roger Haar <haar@PHYSICS.ARIZONA.EDU>]

HI,
    I will take a swing at rephrasing this question. 
First, let me modify the question slightly.  I am thinking of it in
terms of a horseshoe magnet that is spinning about its symmetry axis. 
The magnetic field lines are basically confined to the region between the
poles  or inside the magnet itself/  the electron is sitting
on the axis between the center of the poles.

       A
       X
       I
       S 
       |
     M | M
    M  |  M
   M   |   M
   M   |   M
   N   e   S
       |

As the magnet spins the magnitude of B is constant, but its direction changes, in cylindrical coordinates:
    partial_d B / partial_d t is in the phi direction.
and
      curl of E being in the phi direction.

    Possibly more useful: In rectangular coordinates with the axis being z, and at the moment that B is along y then at the electron ( point (0,0,0):
    partial_d B / partial_d t is in the x direction.
and
      curl of E being in the x direction.

That is the E-field lines form a loop around the x axis.  From what I can figure, the electron does not respond to this field, but I am not sure.

Thanks
Roger Haar U of AZ

************************************************
William Beaty wrote:

On Wed, 23 Jun 1999, John Mallinckrodt wrote:

> On Wed, 23 Jun 1999, William Beaty wrote:
> > ... when an electron moves parallel to the face of a very large, flat
> > magnet where the direction of the field is perpendicular to the face.
> > The electron should "see" the relative motion of the field, and so be
> > deflected perpendicular to this motion and parallel to the magnet face,
> > resulting in a circular path.
>
> All an electron ever "sees" (in the sense of reacting to by virtue of its
> charge) are electric fields.  It is the observer who may see an electron
> "moving through" and reacting to a magnetic field.

Yes, so the question becomes: "does an axially-spinning disk magnet create
a motional e-field which can attract/repel a stationary charged particle?"

CUT