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Re: IONS/forces



Bob Sciamanda wrote:

Ludwik
Are you sure that this isn't sqr(2)*R; (not 2*R)? Or do
I misread you? ....

If the distance were sqr(2)*R instead of 2*R, the pressure
would be 41% higher than 23.56 atmospheres (for Q=0.01 mC,
R=1 cm and a small opening in the shell). My first reaction
was to look for an error in the opposite direction, by orders
of magnitudes; because p was surprisingly large for only
10 micro-coulombs.

The discrepancy is probably connected with the opening
needed to avoid a singularity (at d=R where F must be
calculated). My ring-by-ring integration begins at the rim
of the opening and covers the entire Q-dQ charge. The size
of the small opening has a negligible effect, as shown below.

The force at d=R (on the removed dQ, now treated as a
point-like probe charge) was calculated first. Then it was
divided by the area of the rim circle. For a very small
opening the calculated ratio is identified as pressure.

opening half-angle pressure each ring
(degr) (atm) (degr)

10 20.6237 10
1 23.2597 1
0.1 23.3360 0.1
0.01 23.5638 0.01
0.001 23.5666 0.001

Ludwik Kowalski