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There must be a misunderstanding somewhere. I am reposting the data
at the end of this message. Just plot R=f(v) on the log-log paper
and get n="the best slope". Without doing this I can say that n=2
(plus or minus of up to 20%). Here is my reasoning. The region in
which good data were collected spans from about 2.49 to 4.63 m/s
Thus (v2/v1)=1.8. The corresponding ratio of air resistaces, R2/R1
is 3.0. What is n when 1.8^n=3? It is close to 2.
For your values on n=5 and n=0.2 the force ratios would be 19 and 1.1,
respectively. The experimental data are not perfect but they are
certainly not so bad as to accomodate your range of n. And this has
nothing to do with the value of b (=m*r) in your R=b*v^n formula.