Re: Query about solar azimuth formula

["Paul Camp" <pjcamp@coastal.edu>]

That would be accounted for by the hour angle of the Sun.

> I see that Paul's Sun Altitude agrees with Margaret's.
> But his Sun Azimuth does not account for time of day.
> Perhaps a term is missing?
>
> Brian
>
> At 10:05 11/3/97 EST, Paul Camp wrote:
> > This is the coordinate system transformation taken from Peter 
> > Duffet-Smith's book Practical Astronomy with your Calculator. To go 
> > from equatorial to horizon coordinates:
> >
> > sinA = sinD sinL + cosD cosL cosh
> > cosB = (sinD - sinL sinA)/(cosL cosA
> >
> > This gives you both solar altitude and solar azimuth (I think I 
> > translated from Duffet-Smith's notation correctly)
> >
> > > Paul J. Camp 
>
> [Margaret]
>  calculate A from -
> > >         sinA = sinLsinD + cosLcosDcosh
> > >
> > > where   L = latitude of observer
> > >         D = solar declination
> > >         h = solar hour angle = (t-12) x pi/12  (in radians)
> > >         and t = mean solar time in hours.
> > >
> > >
> > >         (1)  B = -arcsin(-cosDsinh/cosA)
> ------------------------------------------------------------
>
>
> brian whatcott <inet@intellisys.net>
> Altus OK
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