Re: Marilyn, again

[brian whatcott <inet@intellisys.net>]

> At 22:58 8/6/97 -0800, John Mallinckrodt wrote:
> >

> > What's to account for?  For d=365, n=365 the formula gives a value 
> > *very* close to 1 (I get p = 1 - 1.45 x 10^-157) as expected.  For 
> > n=366, 367, ... it gives a value of exactly 1, again as expected.
> >
> > John
>
> Unfortunately, the probability of 366 people having the same
> birthday is not exactly one.
>
> That's what to account for....
>
> Regards
> Brian
Ahem; to put it more succinctly...
It is possible to collect 366 people, no two or more of whom have
 the same birth day number and month number.

Regards
Brian
brian whatcott <inet@intellisys.net>
Altus OK