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How many joules --> e.m. waves?



1) The e.m. waves energy problem (repeated at the bottom of this message)
had an obvious typing error (V=100 volts, not 10, is needed to have 50
joules). It would probably be better if L was actaually given; what is
the purpose of combining two non-trivial tasks?

2) I am puzzled by how small the resistance must be to efficiently convert
the electrostatic energy into the e.m. waves. This is illustrated by the
results of calculations shown below. For the value of R=0.001, specified
in our problem, 99.9% of electrostatic energy is turned into heat.

R(ohms) --> 0.001 0.0001 0.00001

% e.m. --> 0.1 36.9 90.5

All calculations were performed by assuming that L=20 nH. Does anybody
know what is a typical energy efficiency of a broadcasting station?

3) The calculations were performed by using the formula for the current
i(t) in the serial LCR circuit. The reference used was "Principles of
Electricity" by Page and Adams (fourth edition, 1969). As usual, the
formula for i(t) is parametrized in terms of Q(0)=initial charge,
alpha=0.5*R/L and omega_zero= sqrt[1/(L*C)-alph^2). In our problem:
q(0)=1, alpha=0.5*R/L=25000 and omega-zero=66144, all in SI units).
The formula, derived on pages 300-301), is:

i(t)=i(0)*exp(-alpha*t)*sin((omega_zero*t)

where i(0)=[(omega_zero^2+alph^2)*C*V(0)]/omega_zero. Note that our
V(0)=100 volts and C*V(0) is the initial charge on the capacitor, Q(0).

4) Once the formula is written it can be used to find H (as an integral
of i^2*R*dt between zero and infinity). Analytical integration is
likely to be easy but being out of practice with this craft I simply
wrote a short program to do this numerically on my Mac. The energies of
the e.m. waves were then calculated as 0.5*C*V^2-H. All exotic forms of
energy (neutrinos, gravitons, etc.) were ignored.

5) The textbbok I used reminded my that first radio waves were detected
in 1888. "The oscillator used by Hertz consisted essentially of a
capacitor discharging through an inductance and resistance". Does
anybody know the values of C, R, L and V for his setup? I would be glad
to calculate the corresponding energy conversion efficiency.
............................................................................
6) Here is the original wording of our problem; it was part of an
observation that the common capacitor-discharge-current formula,
i(t)=(V/R)*exp(-t/R*C), is in conflict with the emission of e.m. waves
and that L must also be considered. This morning Brian reminded us that
the exponential pulse can be decomposed (Fourier) into a broad spectrum
of sinusoidal components. This not enough to provide for the generation
of sinusoidal waves.

Suppose that V=100 volts, C=0.01 farads (50 joules of energy is available)
and that R=0.001 ohms. To simplify assume that the wire through which the
current is flowing is a circular loop whose radius is 2 cm. How many joules
are taken away in the form of electromagnetic waves?
Ludwik Kowalski