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... Why does the result (half the energy goes
elsewhere) *not* depend on these particular details? If the only loss were
radiative, you'd get 1/2 for the energy loss. If the only loss were
resistive, you'd get 1/2. If it is a combination of both, you'd get 1/2.
I chose identical capacitors, which is one reason you get 1/2, but that
was only for convenience of discussion. The principle (if there is one)
could be applied to any pair of unequal capacitors, and the resulting
fractional energy loss would be a different value.
...
Dr. Donald E. Simanek