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I think you made an oops! Check my math for oops:
56db = 20*Log_10(V2/V1)
V2/V1 = 10^(56/20
V2/V1 = 631 which fits easily into 9 bits.
Those data rates don't seem to present a problem; Shannon says the
limiting bit rate is B*log_2(1+S/N)
Taking a bandwidth B=3000 and a S/N level of 56 db (S/N=10^5.6=398107)
gives 3000*Log_2(398108) = 55808 bits/sec.
A good S/N ratio will get you there!
As regards the bandwidth of a standard telephone line, I have seen
both the range (300-3300)Hz and the range (300-3400)Hz quoted in
the literature. If crucial, I'll dig out a reference. Your figures
may represent an older standard.