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At time t=n the tractor's location (along the rigid x axis) is
L{n}=10^5+10^5*n=10^5*(n+1) (A)
The location of the bug, at t=n, is given by iterative formula
x{n}=[x{n-1}+1]*(1+1/n) (B)
That formula yields exactly the same values as the non-iterative formula o
which contains a sum of 1/k terms (Uri's notation). As everybody else, I
say that the bug will catch the tractor when L{n}=x{n}. At that moment
x{n}-x{n-1}=LST=10^5 (C)
where LST is the length of the last step.
(the last speed of the bug
is 10^5 cm/s, the same as the speed of the tractor).
I know, from the
sollutions of Chip, Uri or John, that x{n} and x{n-1} are gigantic in
comparison with 10^5. What is one kilometer (10^5 cm) in comparison with
zilions of trip around the universe? Therefore I can assume, while writing
L{n}=x{n}, that x{n}=x{n-1}.
Once I do this I conclude that 1/n --> 0 and
n --> infinity, as shown below. What is wrong?
L{n}=[x{n-1}+1]*(1+1/n) or (D)
L{n}=[L{n}-LST]*(1+1/n) or (E)
L{n}=[L{n}-0]*(1+1/n) (F)
I know that n=10^43429.443 and n--> infinity are practically identical.
But conceptually they are very different. How can a neglection of an
unsignificant term, LST, change a finite solution of a problem into
infinity? Where did I err?