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delta Q = 0 (insulated)
delta W = 0 (cylinder does not fail)
delta U = 0 (the above, and first law)
If the energy of the spark is negligible this is a completely closed
system, but clearly something has happened. It has gotten hot, the
pressure of the gas has gone way up, and the chemistry of the gas inside
has been altered. Are you going to tell me that it is not helpful from
the point of view of understanding to point out that although the
internal energy is the same, chemical energy has been converted to
thermal energy? Unfortunately, I can't talk about it any other way.
Barlow Newbolt
BTW: Jim, what do you call the quantity calculated by kA(delta)T/d in
conduction? Many of us call this the heat flow across a boundary.